Chi Square analysis A researcher wondered if there was any underlying pattern among people who prefer their toilet paper to hang over the top or back again

Chi Square analysis A researcher wondered if there was any underlying pattern among people who prefer their toilet paper
to hang over the top or back against the wall. She suspected that one of these preferences might reflect a
higher-than-usual degree of fastidiousness (that is, she wondered if it might indicate a mild OCD
compulsion toward neatness). She collected data from a large group of college students (n=252) about
their toilet paper hanging preference as well as how they preferred to use it to… complete their toilet
transaction (bunched vs. folded wipe). SPSS-02
Chi Square
Statistics are used much like a drunk uses a lamppost:
For support, not illumination. – Vin Scully
Name: _____________________________________________
A researcher wondered if there was any underlying pattern among people who prefer their toilet paper
to hang over the top or back against the wall. She suspected that one of these preferences might reflect a
higher-than-usual degree of fastidiousness (that is, she wondered if it might indicate a mild OCD
compulsion toward neatness). She collected data from a large group of college students (n=252) about
their toilet paper hanging preference as well as how they preferred to use it to… complete their toilet
transaction (bunched vs. folded wipe).
Observed Frequencies
OVER TOP
UNDER BOTTOM
FOLDED
BUNCHED
112
84
37
19
Part I
Create an SPSS data file ready to be analyzed. You will find pages 474-477 in your textbook to be
very helpful with this (C1 = HANG, C2 = USE, C3 = DATA).
Option 1: Enter in every score (i.e., 252 rows of data) [enter “1” for each row in the data view table].
Option 2: Enter in totals for each cell (in the data view table), then: Data → Weight Cases → Select
variable to weight (e.g., “DATA” if you used my labels above) → OK
Part II
Use SPSS to calculate a Chi Square analysis (test of independence) of the data.
Specifically, you should be able to complete the following summary information from the SPSS
output. DUE: One week from TODAY!
Test of Independence: Analyze → Descriptive Statistics → *Crosstabs + (row/col) → Statistics + (chi
square) → Continue → OK
*Under “cells” you can get expected frequencies (counts).
(In this table, rounding to 1 decimal place is sufficient.)
Expected Count
FOLDED
BUNCHED
OVER TOP
UNDER BOTTOM
(Where appropriate, rounding to 2 decimal places is sufficient.)
Pearson Chi-Square (χ2) =
χ2 =
df
Value
p=
Asymptotic Significance (2-sided)

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